-3000+95x-0.2x^2=0

Solution for -3000+95x-0.2x^2=0 equation:

-3000+95x-0.2x^2=0

a = -0.2; b = 95; c = -3000;
Δ = b2-4ac
Δ = 952-4·(-0.2)·(-3000)
Δ = 6625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6625}=\sqrt{25*265}=\sqrt{25}*\sqrt{265}=5\sqrt{265}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(95)-5\sqrt{265}}{2*-0.2}=\frac{-95-5\sqrt{265}}{-0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(95)+5\sqrt{265}}{2*-0.2}=\frac{-95+5\sqrt{265}}{-0.4}
$